-48-14x+12x^2=0

Solution for -48-14x+12x^2=0 equation:

-48-14x+12x^2=0

a = 12; b = -14; c = -48;
Δ = b2-4ac
Δ = -142-4·12·(-48)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-50}{2*12}=\frac{-36}{24}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+50}{2*12}=\frac{64}{24}
=2+2/3
$